Homework due Nov. 17 | Name: | Section: |
Three cubical blocks of equal volume are suspended from strings. Blocks A and B have the same mass and block C has less mass. Each block is lowered into a fish tank and they hang at rest as shown in the figure at the right.
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In the picture shown below are 5 blocks. The blocks have equal volumes but different masses. The blocks are placed in an aquarium tank filled with water and blocks 2 and 5 come to rest as shown in the lower figure. Sketch on the figure where you would expect the blocks 1, 3, and 4 to come to rest. (The differences in mass between successive blocks is significant — not just a tiny amount.)
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Water is poured to the same level in each of the three vessels shown. Each vessel has the same base area. Since the water is to the same depth in each vessel, each will have the same pressure at the bottom. Since the area and pressure is the same, each liquid should exert the same force on the base of the vessel. Yet, if the vessels are weighed, three different values are obtained. (The one in the center clearly holds less liquid than the one at the left, so it must weigh less.) How can you justify this apparent contradiction?
The sum of the pressures on all the surfaces of the vessels must add up to the weight of the contained liquid. In the left vase the pressures on the slanted sides have a component downward, which adds to the force from the pressure on the bottom, corresponding to the larger weight of the liquid. Similarly the pressure force on the sides of the middle vase is upward, decreasing the total force on the vessel.